g^2+(2/3g)+(1/9)=0

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Solution for g^2+(2/3g)+(1/9)=0 equation: 


g in (-oo:+oo)

g^2+(2/3)*g+1/9 = 0

g^2+2/3*g+1/9 = 0

DELTA = (2/3)^2-(1/9*1*4)

DELTA = 0

g = -2/3/(1*2)

g = -1/3 or g = -1/3

g in { -1/3, -1/3 }

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